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Physics 1 · Unit 4: Energy · 14 min read · Updated 2026-05-11

AP Physics 1 Work and Kinetic Energy — AP Physics 1

AP Physics 1 · Unit 4: Energy · 14 min read

1. Mechanical Work by a Constant Force ★★☆☆☆ ⏱ 4 min

W = \vec{F} \cdot \vec{d} = Fd\cos\theta

Where $\theta$ is the angle between the force and displacement vectors, and the SI unit of work is the joule ($1\ \text{J} = 1\ \text{N} \cdot \text{m}$). Only the component of force parallel to displacement does work. Perpendicular components do zero work because $\cos 90^\circ = 0$. Work is positive when energy is added to the object ($\theta < 90^\circ$) and negative when energy is removed ($\theta > 90^\circ$). Net work is the algebraic sum of work done by all individual forces.

Exam tip: Always confirm which axis the problem's given angle is measured from. If the angle is given from the vertical instead of the horizontal, use $\sin\theta$ instead of $\cos\theta$ to get the parallel component of force.

2. Kinetic Energy and the Work-Energy Theorem ★★☆☆☆ ⏱ 4 min

K = \frac{1}{2}mv^2

W_{\text{net}} = \Delta K = K_f - K_i = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

This theorem is a powerful alternative to Newtonian kinematics for problems relating speed and displacement, eliminating the need to calculate acceleration first.

Exam tip: If a problem gives displacement and asks for speed, always check if the work-energy theorem is faster than kinematics. It will save you 1-2 minutes on most MCQ questions.

3. Work Done by a Variable Force ★★★☆☆ ⏱ 3 min

When force varies with position (e.g., spring force, changing applied force), the constant-force work formula does not apply. For AP Physics 1, work done by a variable force is equal to the total area under a force vs. position ($F$ vs. $x$) graph between the initial and final position.

Exam tip: If the force crosses from positive to negative on the $F-x$ graph, don't forget to subtract the area of the negative region, don't just add all areas regardless of sign.

4. Power ★★☆☆☆ ⏱ 3 min

Average power over a time interval $\Delta t$ is given by:

P_{\text{avg}} = \frac{W}{\Delta t}

For instantaneous power (power at a specific moment), when force $F$ is parallel to velocity $v$, the formula simplifies to:

P = Fv

This is commonly used for problems involving engines, vehicles, or human movement where power output is given.

Exam tip: Always convert kilowatts to watts (multiply by 1000) before calculating energy or time. A common mistake leaves power in kilowatts and gets a time 1000 times smaller than the correct value.

Common Pitfalls

Why: Students memorize the simplified $W=Fd$ for parallel forces and forget to adjust for angled forces.

Why: Students confuse "work done by the applied force" with "net work from all forces".

Why: Students are used to working with velocity and force vectors, so they carry over vector addition to kinetic energy.

Why: Students remember "area equals work" but forget force direction changes the sign.

Why: Students memorize the simplified power formula and use it for any problem.

Quick Reference Cheatsheet

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