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Precalculus · Unit 1: Polynomial and Rational Functions · 14 min read · Updated 2026-05-11

Change in tandem (function behavior) — AP Precalculus

AP Precalculus · Unit 1: Polynomial and Rational Functions · 14 min read

1. Average and Instantaneous Rates of Change ★★☆☆☆ ⏱ 4 min

The foundation of analyzing change in tandem (co-variation) is quantifying how much a function's output changes for a given change in input. This connects graphical, algebraic, and numerical descriptions of function behavior.

\text{AROC} = \frac{f(b) - f(a)}{b-a}

AROC equals the slope of the secant line connecting the points $(a, f(a))$ and $(b, f(b))$, describing average behavior over the entire interval.

\text{IROC} = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h} = f'(a)

2. Increasing/Decreasing Behavior and Local Extrema ★★★☆☆ ⏱ 4 min

We use the sign of the instantaneous rate of change (first derivative) to describe whether a function is growing or shrinking over an interval.

  • A function is **increasing** on interval $I$ if $f'(x) > 0$ for all $x \in I$: for any $x_1 < x_2$, $f(x_1) < f(x_2)$.
  • A function is **decreasing** on interval $I$ if $f'(x) < 0$ for all $x \in I$: for any $x_1 < x_2$, $f(x_1) > f(x_2)$.

For a degree $n$ polynomial, the maximum number of local extrema (turning points) is $n-1$.

3. Concavity and Inflection Points ★★★☆☆ ⏱ 4 min

Concavity describes how the rate of change itself changes as input changes, making it a core concept for change in tandem: it is change in the rate of change.

  • A function is **concave up** on interval $I$ if $f''(x) > 0$: the slope of the tangent line increases as $x$ increases, and the graph curves upward.
  • A function is **concave down** on interval $I$ if $f''(x) < 0$: the slope of the tangent line decreases as $x$ increases, and the graph curves downward.

A zero of $f''(x)$ is not automatically an inflection point. For a degree $n$ polynomial, the maximum number of inflection points is $n-2$.

4. AP-Style Practice ★★★★☆ ⏱ 6 min

Common Pitfalls

Why: Students assume any zero of the second derivative is automatically an inflection point, without checking for a sign change. For $f(x)=x^4$, $f''(x)=12x^2$ which is positive on both sides of $x=0$, so concavity does not change.

Why: Students confuse interval-by-interval increasing behavior with global behavior, ignoring that $f(1) = -1 < f(3) = 1$, which violates the definition of an increasing function.

Why: Students mix up the order of subtraction in the numerator, leading to a sign error.

Why: Students forget that $x=2$ is a hole, so the function is not defined at that point and cannot be an extremum.

Why: Students confuse concavity (change in the rate of change) with increasing/decreasing behavior (the sign of the rate of change itself).

Quick Reference Cheatsheet

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